WebMar 1, 2024 · pH is a measure of acidity or hydrogen ion concentration, while pOH is a measure of alkalinity or hydroxide ion concentration. If you know pH, it's easy to calculate pOH because pH + pOH = 14. Sometimes … WebDec 12, 2024 · Sr (OH) ₂ solution is a base with valence 2, so we determine the pOH from the OH ion concentration - which is expressed by pOH = - log [OH -]. After that we determine the pH value from the relationship: [H⁺] [OH⁻] = Kw=10⁻¹⁴ pH + pOH = 14 Sr (OH)₂⇒Sr²⁺+2OH⁻ From equation [Sr (OH)₂] : [OH⁻]=1 : 2, so [OH⁻]= Advertisement aliasger2709
What is the pH of a 0.020 M nitric acid solution? - Answers
WebDetermine the pH of a 0.010 M HNO3 solution A. 4.01 OB 2.0 O C.7.0 O B.5.0 This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Question: Determine the pH of a 0.010 M HNO3 solution A. 4.01 OB 2.0 O C.7.0 O B.5.0 Show transcribed image text Expert Answer Web9. The relationship that exists between the p Ka of a weak acid and the strength of the weak acid is A. The larger the value ofpKa, the stronger the acid. B. The value ofpKa is equal to Kw / [weak acid] C. The value of p Ka is not related to the strength of a weak acid. D. The value ofpKa is equal to Kw/K a for the weak acid E. ncs nova 消された理由
What is the pH of a 0.0001 M solution of HNO3? pOH?
WebAt 25°C we know it to be 1.0 x 10^(-14), but at something like 50°C it's about 5.5 x 10^(-14). When we do the math using the Kw at 50°C to find the pH and pOH we find that they are both lower than 7, simply meaning that there more hydronium and hydroxide ions in neutral water at higher temperatures. Hope that helps. WebJun 15, 2024 · pOH = -log[OH – ] pOH = -log(0.25) pOH = 0.60. Think about the answer and whether it makes sense. This is a strong base solution, so you expect it has a high pH … WebApr 15, 2024 · pOH = − log[0.0020] pOH = 2.70 ; pH = 14 − 2.70 = 11.3 A strong base is fully dissociated, so the concentration of the ion is the same as the original compound - 0.0020M, or 0.0020 mol/L The [H +] is found from the calculated pH we obtained. pH = −log[H +] 11.3 = − log[H +] ; [H +] = 5.01 × 10−12 mol/L Answer link ncs ウエイトレンタル